745 Changes

November 11, 2018
images u
  • {"poster"=>{"file_path"=>"/qMRlMLrpl9Axih06XuIWzJMtVBc.jpg", "iso_639_1"=>nil}}
  • {"poster"=>{"file_path"=>"/qMRlMLrpl9Axih06XuIWzJMtVBc.jpg", "iso_639_1"=>"en"}}
images a
  • {"poster"=>{"file_path"=>"/qMRlMLrpl9Axih06XuIWzJMtVBc.jpg"}}
images a
  • {"poster"=>{"file_path"=>"/mKiKN6HNT3OFvQycHZDyPDfc0xH.jpg"}}
November 3, 2018
season u
  • {"season_id"=>30121, "season_number"=>1}
season u
  • {"season_id"=>30122, "season_number"=>2}
season u
  • {"season_id"=>30123, "season_number"=>3}
season u
  • {"season_id"=>62206, "season_number"=>4}
November 1, 2018
images a
  • {"backdrop"=>{"file_path"=>"/79DgItjsyH5tpA3mC2xv5gU2zlZ.jpg"}}
October 16, 2018
season_regular u
  • {"add_to_every_season"=>true, "character"=>"Jon Vatson", "credit_id"=>"52585c90760ee34661116db4", "order"=>1, "person_id"=>7060}
  • {"add_to_every_season"=>true, "character"=>"John Watson", "credit_id"=>"52585c90760ee34661116db4", "order"=>1, "person_id"=>7060}
season_regular u
  • {"add_to_every_season"=>true, "character"=>"Sherlok Xolms", "credit_id"=>"52585c90760ee34661116d96", "order"=>0, "person_id"=>71580}
  • {"add_to_every_season"=>true, "character"=>"Sherlock Holmes", "credit_id"=>"52585c90760ee34661116d96", "order"=>0, "person_id"=>71580}
October 14, 2018
season u
  • {"season_id"=>62206, "season_number"=>4}
season u
  • {"season_id"=>30123, "season_number"=>3}
season u
  • {"season_id"=>30122, "season_number"=>2}
season u
  • {"season_id"=>30121, "season_number"=>1}
September 24, 2018
name a
  • Σέρλοκ
September 23, 2018
season_regular u
  • {"add_to_every_season"=>true, "character"=>"John Watson", "credit_id"=>"52585c90760ee34661116db4", "order"=>1, "person_id"=>7060}
  • {"add_to_every_season"=>true, "character"=>"Jon Vatson", "credit_id"=>"52585c90760ee34661116db4", "order"=>1, "person_id"=>7060}
season_regular u
  • {"add_to_every_season"=>true, "character"=>"Sherlock Holmes", "credit_id"=>"52585c90760ee34661116d96", "order"=>0, "person_id"=>71580}
  • {"add_to_every_season"=>true, "character"=>"Sherlok Xolms", "credit_id"=>"52585c90760ee34661116d96", "order"=>0, "person_id"=>71580}
alternative_titles a
  • {"title"=>"Sherlok Xolms", "iso_3166_1"=>"UZ"}
uz-UZ
name a
  • Sherlok
translations a
  • uz-UZ
September 11, 2018
season u
  • {"season_id"=>30121, "season_number"=>1}
season u
  • {"season_id"=>30122, "season_number"=>2}
season u
  • {"season_id"=>30123, "season_number"=>3}
season u
  • {"season_id"=>62206, "season_number"=>4}
July 31, 2018
videos a
  • {"id"=>"5b6052830e0a263fb000d4ec", "name"=>"Sherlock [BBC] Trailer PT-PT", "key"=>"Orkng7s-GtA", "size"=>720, "type"=>"Trailer"}
name a
  • Sherlock
July 3, 2018
plot_keywords a
  • {"name"=>"misanthrope", "id"=>9622}
plot_keywords d
  • {"name"=>"misanthrophy", "id"=>204918}
June 8, 2018
lt-LT
overview a
  • Londonas, 2010. Jis kariavo Afganistane ir buvo sužeistas. Grįžęs į gimtąjį kraštą jis susipažysta su paslaptingu, bet genialiu asmenimi. Londone įvyksta neaiškių žmogžudysčių serija. Skotland Jardas neįsivaizduoja ko imtis. Tik vienas asmuo galėtų išspręsti šias problemas ir rasti atsakymus į sudėtingiausius klausimus. Modernus serialas apie garsųjį seklį ir jo draugą daktarą, tyrinėjančius 21-ojo amžiaus nusikaltimus.
May 29, 2018
season_regular a
  • {"add_to_every_season"=>false, "character"=>"Irene Adler", "credit_id"=>"54a2ff7ec3a3686428000bbc", "order"=>16, "person_id"=>213083, "season_id"=>62206}
May 27, 2018
season u
  • {"season_id"=>62206, "season_number"=>4}
season u
  • {"season_id"=>30123, "season_number"=>3}
season u
  • {"season_id"=>30122, "season_number"=>2}
season u
  • {"season_id"=>30121, "season_number"=>1}
May 8, 2018
season u
  • {"season_id"=>62206, "season_number"=>4}
season u
  • {"season_id"=>30123, "season_number"=>3}
season u
  • {"season_id"=>30122, "season_number"=>2}
season u
  • {"season_id"=>30121, "season_number"=>1}
April 29, 2018
season u
  • {"season_id"=>30121, "season_number"=>1}
season u
  • {"season_id"=>30120, "season_number"=>0}
gl-ES
overview a
  • Serie baseada nas obras de Sir Arthur Conan Doyle, que trae até nós a oportunidade de ver como sería Sherlock Holmes aplicando os seus métodos dedutivos en plena Londres do século XXI.
translations a
  • gl-ES
April 28, 2018
network d
  • {"name"=>"PBS", "id"=>14}
network d
  • {"name"=>"France 4", "id"=>511}
April 21, 2018
lt-LT
name u
  • Serlokas
  • Šerlokas
April 20, 2018
season u
  • {"season_id"=>30120, "season_number"=>0}
ru-RU
videos u
  • {"id"=>"5ad9c4bb9251415901009572", "name"=>"Сериал \"Шерлок\". Трейлер", "key"=>"4lDypCGRLgA", "size"=>720, "type"=>"Trailer"}
  • {"id"=>"5ad9c4bb9251415901009572", "name"=>"Сериал \"Шерлок\". Трейлер", "key"=>"4lDypCGRLgA", "size"=>480, "type"=>"Trailer"}
ru-RU
videos u
  • {"id"=>"5ad9c4bb9251415901009572", "name"=>"Сериал \"Шерлок\" Трейлер.", "key"=>"4lDypCGRLgA", "size"=>720, "type"=>"Trailer"}
  • {"id"=>"5ad9c4bb9251415901009572", "name"=>"Сериал \"Шерлок\". Трейлер", "key"=>"4lDypCGRLgA", "size"=>720, "type"=>"Trailer"}
ru-RU
videos u
  • {"id"=>"5ad9c4bb9251415901009572", "name"=>"Сериал \"Шерлок\". Русский трейлер.", "key"=>"4lDypCGRLgA", "size"=>720, "type"=>"Trailer"}
  • {"id"=>"5ad9c4bb9251415901009572", "name"=>"Сериал \"Шерлок\" Трейлер.", "key"=>"4lDypCGRLgA", "size"=>720, "type"=>"Trailer"}
ru-RU
videos a
  • {"id"=>"5ad9c4bb9251415901009572", "name"=>"Сериал \"Шерлок\". Русский трейлер.", "key"=>"4lDypCGRLgA", "size"=>720, "type"=>"Trailer"}
ru-RU
videos u
  • {"id"=>"5ad9c2cac3a3683c6600933a", "name"=>"Шерлок. Неудачные дубли (RUS VO)", "key"=>"cc8Ntk6-yng", "size"=>720, "type"=>"Featurette"}
  • {"id"=>"5ad9c2cac3a3683c6600933a", "name"=>"Шерлок. Неудачные дубли", "key"=>"cc8Ntk6-yng", "size"=>720, "type"=>"Featurette"}
ru-RU
videos a
  • {"id"=>"5ad9c2cac3a3683c6600933a", "name"=>"Шерлок. Неудачные дубли (RUS VO)", "key"=>"cc8Ntk6-yng", "size"=>720, "type"=>"Featurette"}
production_companies a
  • {"name"=>"France Télévisions", "id"=>11795}
network a
  • {"name"=>"France 4", "id"=>511}
April 19, 2018
season u
  • {"season_id"=>62206, "season_number"=>4}
April 3, 2018
season u
  • {"season_id"=>30123, "season_number"=>3}
March 24, 2018
season u
  • {"season_id"=>62206, "season_number"=>4}
season u
  • {"season_id"=>30123, "season_number"=>3}
season u
  • {"season_id"=>30122, "season_number"=>2}
season u
  • {"season_id"=>30121, "season_number"=>1}
season u
  • {"season_id"=>30120, "season_number"=>0}
videos u
  • {"id"=>"59de0e25c3a36861df094a89", "name"=>"Тизер 3 сезона", "key"=>"gPxBLpUFTOk", "size"=>1080, "type"=>"Teaser"}
  • {"id"=>"59de0e25c3a36861df094a89", "name"=>"Шерлок: Тизер 3-го сезона (2013)", "key"=>"gPxBLpUFTOk", "size"=>1080, "type"=>"Teaser"}
videos u
  • {"id"=>"591ae95cc3a368423c06c0c4", "name"=>"Трейлър - Сезон 3", "key"=>"pWXYvHQGj9A", "size"=>720, "type"=>"Trailer"}
  • {"id"=>"591ae95cc3a368423c06c0c4", "name"=>"FOX Crime - Шерлок, сезон 3", "key"=>"pWXYvHQGj9A", "size"=>720, "type"=>"Trailer"}
videos u
  • {"id"=>"58fa294d925141588600d0cc", "name"=>"Sherlock", "key"=>"xK7S9mrFWL4", "size"=>720, "type"=>"Trailer"}
  • {"id"=>"58fa294d925141588600d0cc", "name"=>"Sherlock Trailer - Season 1 [TEH]", "key"=>"xK7S9mrFWL4", "size"=>720, "type"=>"Trailer"}
March 23, 2018
videos u
  • {"id"=>"57f2c0ba9251410c2e00255d", "name"=>"Bande Annonce VF", "key"=>"640ClSZxN98", "size"=>480, "type"=>"Trailer"}
  • {"id"=>"57f2c0ba9251410c2e00255d", "name"=>"Sherlock avec Benedict Cumberbatch - Bande Annonce VF - 2010", "key"=>"640ClSZxN98", "size"=>480, "type"=>"Trailer"}
videos u
  • {"id"=>"56b553dd9251416615000a35", "name"=>"Sherlock", "key"=>"rxHtCf2q9GI", "size"=>360, "type"=>"Trailer"}
  • {"id"=>"56b553dd9251416615000a35", "name"=>"La novia abominable | Sherlock | TNT", "key"=>"rxHtCf2q9GI", "size"=>360, "type"=>"Trailer"}
March 20, 2018
season u
  • {"season_id"=>62206, "season_number"=>4}
March 19, 2018
season u
  • {"season_id"=>30120, "season_number"=>0}
March 18, 2018
twitter_id a
  • Sherlock221b
facebook_id a
  • Sherlock.BBCW
March 11, 2018
season u
  • {"season_id"=>62206, "season_number"=>4}
March 3, 2018
season u
  • {"season_id"=>30120, "season_number"=>0}
February 26, 2018
status u
  • Planned
  • Returning Series
February 17, 2018
status u
  • Returning Series
  • Planned
certifications a
  • {"iso_3166_1"=>"DE", "certification"=>"12"}
January 20, 2018
season u
  • {"season_id"=>30120, "season_number"=>0}
January 16, 2018
season u
  • {"season_id"=>30120, "season_number"=>0}
January 13, 2018
images d
  • {"backdrop"=>{"file_path"=>"/2D8szEb4FG0biNtUqkC4f21XcxR.jpg"}}
images d
  • {"backdrop"=>{"file_path"=>"/6lSgq7w3pxJ82OscgshRCDVpzLC.jpg"}}
January 11, 2018
season u
  • {"season_id"=>62206, "season_number"=>4}
season u
  • {"season_id"=>30121, "season_number"=>1}
December 18, 2017
overview u
  • 2010년 7월 BBC One에서 방영을 시작한 추리물. 아서 코난 도일의 셜록 홈즈 시리즈를 원작으로 현대적으로 재구성하였다. 아프가니스탄에서 군의관으로 복무 중이었으나, 전투 중 부상을 입고 의병 제대한 후 존 왓슨은 우연히 만난 옛 친구 마이크 스탬포드를 통해 셜록 홈즈를 소개받고 허드슨 부인이 세를 놓는 방에 함께 사는 룸메이트가 된다. 과거 허드슨 부인에게 도움을 준 인연으로 그녀의 건물에 세들어 있는 셜록은 자신을 고기능 소시오패스라고 당당하게 공인하는 괴짜 탐정. 왓슨은 얼떨결에 셜록의 조수 역할로 미스테리한 살인 사건 수사에 동참하는데...
  • 2010년 7월 BBC One에서 방영을 시작한 추리물. 아서 코난 도일의 셜록 홈즈 시리즈를 원작으로 현대적으로 재구성하였다. 아프가니스탄에서 군의관으로 복무 중이었으나, 전투 중 부상을 입고 의병 제대한 후 존 왓슨은 우연히 만난 옛 친구 마이크 스탬포드를 통해 셜록 홈즈를 소개받고 허드슨 부인이 세를 놓는 방에 함께 사는 룸메이트가 된다. 과거 허드슨 부인에게 도움을 준 인연으로 그녀의 건물에 세들어 있는 셜록은 자신을 고기능 소시오패스라고 당당하게 공인하는 괴짜 탐정. 왓슨은 얼떨결에 셜록의 조수 역할로 미스테리한 살인 사건 수사에 동참하는데...
December 14, 2017
season u
  • {"season_id"=>30123, "season_number"=>3}
December 10, 2017
season u
  • {"season_id"=>30120, "season_number"=>0}
November 24, 2017
season u
  • {"season_id"=>62206, "season_number"=>4}
season u
  • {"season_id"=>30123, "season_number"=>3}
season u
  • {"season_id"=>30122, "season_number"=>2}
season u
  • {"season_id"=>30120, "season_number"=>0}
season u
  • {"season_id"=>30121, "season_number"=>1}
November 2, 2017
alternative_titles a
  • {"title"=>"新编夏洛克", "iso_3166_1"=>"CN"}
alternative_titles a
  • {"title"=>"神探夏洛克", "iso_3166_1"=>"CN"}
alternative_titles a
  • {"title"=>"新福尔摩斯", "iso_3166_1"=>"HK"}
zh-CN
name u
  • 新福尔摩斯
  • 神探夏洛克
October 26, 2017
season u
  • {"season_id"=>30120, "season_number"=>0}
season u
  • {"season_id"=>62206, "season_number"=>4}
season u
  • {"season_id"=>30123, "season_number"=>3}
season u
  • {"season_id"=>30122, "season_number"=>2}
season u
  • {"season_id"=>30121, "season_number"=>1}
no-NO
overview a
  • I denne nyversjonen av Sir Arthur Conan Doyles populære mysterier, saumfarer den eksentriske detektiven gatene i det moderne London på jakt etter ledetråder.
translations a
  • no-NO

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