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Item: James Bond Collection

Language: en-US

Type of Problem: Incorrect_content

Extra Details: "Never Say Never Again" should not be in this collection. It is not an officially recognized Bond film by the distributor of all of the other James Bond films.

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Hi, the collection is fundamentally against our rules (but it is our most notable exception). The exception is that it is based on the James Bond action character (spoof comedies not included). It is not a collection to reflect the official box set. I hope that makes some sense. Thanks.

Interesting, I feel like most people would put Never Say Never Again and Casino Royale (1967) in the same bracket, neither of them are official, neither of them are included in any of the James Bond blu ray collection sets, neither are recognised by EON, I understand your reasoning but I feel like it needs to be re-evaluated.

They should be broken by actor (Connery, Brosnan, Craig).

@1LOSTFan said:

They should be broken by actor (Connery, Brosnan, Craig).

Strictly based on the rules, this collection shouldn't exist. This is our only exception and, as such, it will remain as it is.

Can the collection still be broken up into certain actors?

@1LOSTFan said:

Can the collection still be broken up into certain actors?

As indicated, it will remain as is.

Random question I guess but why does this exception exist?

Can someone explain to me why Casino Royale (1967) isn't included in this collection, but Never Say Never Again (1983) is? The most natural solution would be to include them both, or neither (since they aren't Eon Productions).

I would appreciate the underlying reason instead of 'the collection will remain as is', as indicated above. Thanks!

@Ik-Stan said:

Can someone explain to me why Casino Royale (1967) isn't included in this collection, but Never Say Never Again (1983) is? The most natural solution would be to include them both, or neither (since they aren't Eon Productions).

I would appreciate the underlying reason instead of 'the collection will remain as is', as indicated above. Thanks!

Read all the replies above and you will notice it was already answered.

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